Sheafification
Last time: for a space X and a ring k, a presheaf is a functor , and a sheaf is a presheaf F such that for any open U in X and any open cover
of U, the sequence

is exact.
If we let X=*, then the functor is an equivalence. Note this isn’t true for presheaves because you also have to assign the empty set to something as well.
Examples:
- Constant sheaf
- For a point x in X, the “skyscraper sheaf” at x
- The sheaf of functions on X, denoted
, defined by
. This is a sheaf because functions glue in an obvious way
- If
is a k-vector bundle, then we get a sheaf of sections: for open subset U of B, let
.
In fact, we saw previously that an sheaf can be thought of as a sheaf of sections for some bundle-like object

Following this idea:
Proposition: For any presheaf F on X, there is a sheaf and a morphism
such that for any sheaf G on X and morphism
there is a unique map
such that
.
is called the sheafification of the presheaf F.
Sketch of proof: We’ll turn the big weird equation before the proposition into a definition. Define:

Note that if , let
by
. This defines our map
. Remains to check the universal property.
Given a sheaf G on X, and , we want to define
. Consider U open in X, and
. Choose an open cover
of U, and for each
choose a section
such that
for each y in
. Then
because the germs of both sides at
are
. But G is a sheaf, so the
glue to give a unique element
. Let
.
To summarize: the map induces isomorphism

This says that sheafification is a left adjoint to the forgetful functor .
Abelian Categories
We’re going to show Sh(X;k) is an abelian category so we can use homological algebra!
Definition: A category C is additive if
(A1) for object X and Y in C, is an abelian group, and composition
is a group homomorphism
(A2) there is a zero object, 0 in C, such that (exercise: this is equivalent to saying that 0 is initial and terminal in C)
(A3) C has biproducts, called direct sum
Examples of additive categories:
- the category of abelian groups, Ab
- PreSh(X;k)
- Sh(X;k)
Definition: Let be a morphism. We say that
has kernel
if there is a morphism
such that
, and for any
such that
, then there is a unique
such that
.

Example: Let F and G be sheaves on X, and . Let
. Check that
is a sheaf on X and is indeed the kernel of
in the category Sh(X).
We’ll continue with abelian categories next time.
2 thoughts on “Algebraic Analysis notes Lecture 7 (25 Jan 2019)”